请教 Erlenmeyer-plochl反应机理? 1. 醋酐和乙酰氨基乙酸 to form the the mixed anhydride. 2. isomerization of the ch3coch to the enol 3. oh of enol attack the co of mixed anhydride to form the lactone and eliminate ch3coo-. 4. deprotonation of the ch, attack 苯甲醛, lose 1 molecule of h2o to form the product. 5. product might be able to hydrolyzed at work up, which i am not sure. [em05]查看更多