两篇关于分析LSV得出析氧过电位分析,不太明白,求解?看了两篇文献,关于LSV曲线分析的结果刚好相反,不知哪一个说法正确?一、文献如图,Fig. 3displays the linear voltammograms of different electrodes in 0.5 M Na2SO4 solution at 25 8C and a scan rate of 10 mV/s. It is clearly shown that the CNT-Bi-PbO2 electrode had an oxygen evolution overpotential of 1.61 V (vs. SCE) which was higher than those ofPbO2, Bi-PbO2 and CNT-PbO2 of 1.50, 1.55 and 1.50 V (vs. SCE), respectively. 有点不懂,析氧电位也就是析氧过电位吧?文献上说析氧过电位的大小是顺序是d>c>b>a。也就是说图形越低的,析氧电位越小,不知对不?看另外一篇文献。二、文献如图,Fig. 4, the OEPs were 2.16 V and 2.23 V (vs. SCE) for the Ti/SnO2-Sb electrode and the Ti/SnO2-Sb-CNT electrode, respectively.这篇文献上说,析氧电位的大小是b>a,也就是说图形越低的析氧电位越大。 综合两篇文献分析,让人费解,希望朋友们帮解。谢谢,BaiduShurufa_2014-7-18_21-3-23.png2.png查看更多7个回答 . 8人已关注