帮忙鉴别软件名字？ my company my address my city design calculations 2016-12-17 revision : vessel: 1, bay no. 1. maximum allowablepressure. [ vessel: gs446, bay no. 1 ] vessel in operation = 1.427 mpa vessel in test = 2.438 mpa bundletube under internal pressure. [ vessel: gs446, bay no. 1 ] material : sa179 seamless tube temperature in operation : t = 221 °c weld joint efficiency : e = 1 carbon steel nominal thickness : tn = 2.11 mm external diameter : do = 25.40 mm outside radius : ro = 12.70 mm p = internal pressure s = allowable stress ca = corrosion + tolerance asme viii div.1 2015 appendix minimum required thickness circular stress maximum allowable pressure 1-1 (a)(1) file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image002.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image004.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image006.png 1-2 (a)(1) p 0.385 se ú tn r /2 file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image008.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image010.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image012.png 1-2 (a)(2) p 1.25 se ú tn r /2 file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image014.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image016.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image018.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image020.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image022.png file:///c:/users/wd/appdata/local/temp/msohtmlclip1/01/clip_image020.png p (mpa) s (mpa) t + ca (mm) s (mpa) ca (mm) pa (mpa) horizontal test operation 1.6133 1.241 161.1 92.4 0.13 0.17 9.07 6.97 0.00 0.00 28.6708 16.4443 cross view. [ vessel: gs446, bay no. 1 ] tubes diameter = 25.4 mm length = 9,144 mm horizontal pitch = 62 mm vertical pitch = 53.69 mm tube-to-tubesheetjoint. [ vessel: gs446, bay no. 1 ] weight of sliding header (with 750 mm length of tube) : w = 1,888.3 dan st = 92.4 mpa tt = 2.11 mm dt = 25.4 mm nt = 240 s = 138 mpa et = 190,740 mpa lt = 9,144 mm friction factor : m = 0.3 axial load due to thermal expansion : f = m w = 566.5 dan axial stress : s t = f / nt / [ p ( dt - tt ) tt ] = 0.153 mpa allowable stress : welded tubes : st,j = min[ (min( s ; st ) g / tt ) ; st ] ( g = weld ) st,j = 73.92 mpa expanded joint : st,j = 0.8 min( s ; st ) (with 2 grooves) maximum allowable differential thermal expansion : d l max = [( st,j - s t ) / et ] lt = 3.536366 mm 诸位大虾，请教这个软件的名字啊 查看更多
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