求LiI/pyridine水解甲酯成酸的机理？ 求LiI/pyridine水解 甲酯 成酸的机理 Procedure: To a solution of compound A (38 g, 0.12 mol) in pyridine (250 mL) was added lithium iodide (38 g, 0.28 mmol), and the resulting solution was heated at reflux for 2 h. The reaction mixture was cooled to room temperature and the pyridine removed under vacuum. To the resulting gum was added 1 N HCl (100 mL), the resulting mixture was stirred for 15 min at rt and then filtered in vacuum. The solid was washed with 1 N HCl and Et2O, dried in vacuum to afford compound B (30.0 g, yield : 82.6%) as a white solid compound A is a "methyl ester" compound B is an acid. LiI/pyridine水解甲酯成酸,是不是这样的条件很温和？不能水解别的酯（比如 乙酯 ， 丙酯 ）？ 文献是JMC J. Med. Chem. 1995,38, 98-108 名字：Nonpeptidic Inhibitors of Human Leukocyte Elastase. 5. Design, Synthesis, and X-ray Crystallography of a Series of Orally Active 5-Aminopyrimidin-6-one-ContaininTgr ifluoromethyl Ketones 作者：Chris A. Veale,*ti Peter R. Bernstein,' Craig Bryant,' Christopher Ceccarelli,t James R. Damewood, Jr. ,t Roger Earley,t Scott W. Feeney,? Bruce Gomes,P Ben J. Kosmider,? Gary B. Steelman,' Roy M. Thomas,+ Edward P. Vacek,' Joseph C. Williams,$ Donald J. Wolanin,' and Sheila Woolsont查看更多7个回答 . 3人已关注
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