在刚性支架处填写mu，即摩擦系数，造成死循环？ 解释倒也无所谓，主要是处理办法就是所谓删除“不重要”的节点的mu值？这样做的问题和后果是什么？有推荐 ... 我综合一下大家的方法，再谈一下我的方法。 @wl19891989 @路行天下 三楼和五楼的方法有点绝对， 我的经验不是全部去掉。比如三楼的例子，有可能只去掉260的mu就可以了。 @bdliang 六楼的方法比较接近标准答案。 其实可以在工况编辑器里面把一个工况的摩擦全去掉，去掉后再看计算结果。 @mwchit 10楼的方法我比较认同，但是光看ope的位移报告我认为不够吧，多少看看受力吧（脱空的管道你光看位移不行吧）。 我的观点： 【1】对于按f2的时候，节点比较少的可以简化操作， 把new state closed neg和 new state closed neg sliding err 1的两种节点mu去掉一般就可以了。 这种是对于相去简单的模型，而且对正确结果是有影响的，有时候我偷懒的时候这样做。 【2】我推荐的方法： （1）工况编辑器里面把出现死循环工况的摩擦全去掉。找一下friction multiplier这个选项。 （2）看报告，看受力为0（脱空和不发生相对位移）的节点，去掉它的mu。记得把friction multiplier改回来。 （3）重新看一下报告，看看去掉mu的点，有无相对位移或脱空。 不过（2）-（3）步中还要反复验证的， 因为mu全去掉的结果和实际的结果还是有差别的。 我的方法仅供参考，还请大家指教。 coade官方论坛版主和应力专家richard ay的解释： if during the solution, you click the [f2] key, caesar ii will give you a list of the restraints that are not converged at that time. changing characteristics of any of these restraints may allow the job to converge. details of what this report contains can be found below. for jobs with friction, please read the section on friction in the technical reference manual. additionally, the magnitude of the "coefficient of friction" can be changed globally for all restraints using the "load case options" tab of the static load case editor. i can not say how any one specific boundary condition change will affect the system of equations in [k], and the subsequent matrix decomposition. when you encounter this behavior, all you can do is play with the system, using the list of non-converged restraints as a guide. interpreting the information from the [f2] key: old state - new state: this indicates the status of two successive iterations. the old state is iteration "x", while the new state is iteration "x+1". open - closed: this indicates the status of a directional or gapped restraint. open means the pipe is not on the restraint, while closed means the pipe is contacting the restraint. direction x, y, z: these values define the direction cosine of the restraint. sliding - not sliding: for jobs with friction this indicates whether or not the load was sufficient to cause sliding. details on this can be found in the "friction discussion" in the technical reference manual. error: this value indicates the percent change in the normal force between iterations. a value of 0.5 indicates that the normal force changed by 50%, which means the friction force changed by 50%. 查看更多
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