关于分析方法的方法学?在定量测定物质的标准曲线建立中,文献中写到:Due to the large calibration range, the intercept contributed signi?cantly to the peak area ratios of low concentrated samples. Therefor sample with concentrations above 5mol/l were calculated using all six (respectively eight) calibrators 0.02, 0.5, 5, 10, 30 and 50mol/l (respectively 75 and 100mol/l), whereas samples with concentrations below 5mol/l were calculated using only the ?rst three calibrators.Samples with concentrations below 0.02mol/l as well as samples for which the peak area ratio was below the absolute value of the intercept of its respective three points calibration curve were calculated by proportional conversion using the respective peak area ratio of the ?rst calibration standard.求教各位大神,这么做的意义是什么?1.低浓度点,也就是上文提到的临界点5mol/l 是怎么选择的(为什么以这个为分界点)2.原先以为标准曲线的建立,之后测实际样本,不是直接带入回归方程计算吗,这个为什么高低浓度分开做?3.想知道Due to the large calibration range, the intercept contributed signi?cantly to the peak area ratios of low concentrated samples.这句话的理解初入研究阶段 ,请各位指教 不甚感激查看更多2个回答 . 18人已关注