请较如何根据电容器的充放电曲线计算internal resistance (IR) drop?请问本版超级电容器的各位高人,如何根据电容器的充放电曲线来计算internal resistance (IR) drop?本人以前做锂电的,现在刚刚接触电容器方面的知识,对这一计算着实很迷茫,搞不清,特地来本版请教。1. 请教如何根据电容器的充放电曲线计算internal resistance (IR) drop?看到有文献写到:The internal resistance was determined from the voltage drop at the beginning of each discharge:R=△V(iR为V的下标)/2i,△V(iR为V的下标) is the voltage drop between the first two points from its top cut-off.This voltage drop is also referred to as the iR drop. i is the current applied.2. 想请较高人简单解释或者介绍一下功率和能量 密度计 算公式的由来。看见该文献谈到功率密度和能量密度的计算公式如下:P=V*V/[4RM]? ?&??E=0.5CV*V/Mwhere V is the applied voltage ,R is the internal resistance, M is the total mass of active electrode materials used in electrochemical capactiors, and C is the measrued total capacitance of electrochemical capactiors这与常见的P和E计算公式有出入啊E=It(Ua)/m? ?P=I(Ua)/m其中,I为充放电电流,t为放电时间,Ua为平均工作电压,m为正负极活性材料的质量之和。查看更多7个回答 . 9人已关注